To balance a redox equation using the half-reaction method, the equation is first divided into two half-reactions, one representing oxidation and one representing reduction. The equations for the half-reactions are then balanced for mass and charge and, if necessary, adjusted so that the number of electrons transferred in each equation is the same. Balanced chemical equation - A chemical equation in which the number of each type of atom is equal on the two sides of the equation. Subscripts - Part of the chemical formulas of the reactants and products that indicate the number of atoms of the preceding element. Word Equation. Calcium Nitrate + Sodium Oxalate = Calcium Oxalate + Sodium Nitrate. Ca(NO3)2 + Na2C2O4 = CaC2O4 + NaNO3 is a Double Displacement (Metathesis) reaction where one mole of aqueous Calcium Nitrate [Ca(NO 3) 2] and one mole of aqueous Sodium Oxalate [Na 2 C 2 O 4] react to form one mole of solid Calcium Oxalate [CaC 2 O 4] and two moles of aqueous Sodium Nitrate [NaNO 3] Word Equation. Sodium Sulfate + Lead(Ii) Nitrate = Sodium Nitrate + Lead Sulfate. Na2SO4 + Pb(NO3)2 = NaNO3 + PbSO4 is a Double Displacement (Metathesis) reaction where one mole of aqueous Sodium Sulfate [Na 2 SO 4] and one mole of aqueous Lead(Ii) Nitrate [Pb(NO 3) 2] react to form two moles of aqueous Sodium Nitrate [NaNO 3] and one mole of solid Lead Sulfate [PbSO 4] Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced. Since there is an equal number of each element in the reactants and products of Fe (NO3)3 + 3NaOH = Fe (OH)3 + 3NaNO3, the equation is balanced. Balance the reaction of Fe (NO3)3 + NaOH = Fe Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced. Since there is an equal number of each element in the reactants and products of 2NaOH + H2SO4 = Na2SO4 + 2H2O, the equation is balanced. Balance the reaction of NaOH + H2SO4 = Na2SO4 + H2O Multiplying the number of moles of H A 2 SO A 4 by this factor gives us the number of moles of NaOH needed: 3.16 × 10 − 2 mol H 2 SO 4 × 2 mol NaOH 1 mol H 2 SO 4 = 6.32 × 10 − 2 mol NaOH. Notice how we wrote the mole ratio so that the moles of H A 2 SO A 4 cancel out, resulting in moles of NaOH as the final units. yKsaFe.

na hno3 balanced equation